[杂项项目]纯C语言实现控制台小游戏——数字拼图

一年前写的小游戏，当时感觉小有成就，现在发现缺陷真的很多。不禁感叹，当时为什么会用那么多goto呢。在这里真的建议大家不要用goto。只是现在懒得改了，毕竟是小程序。贴出来供大家参考。如果有时间后序再添加注释。如有问题欢迎评论。

#include <stdio.h>  
#include <stdlib.h>  
#include<math.h>  
#include <time.h>  
#define max 10  
int x, y, step, label = 0;  
typedef struct score {  
    int steps, steps2;  
    double times;  
    char name[18];  
}score;  
score sco[max + 1];  
char ch, buff[3];  
bool flag, flag1 = false;  
clock_t start, finish;  
bool over(){  
    system("cls");  
    printf("\n\n\n\n\t\t\t您共用了 %d 步 ,耗时 %.3f 分钟\n", step, (double)(finish - start) / 40000);  
    system("pause");  
    system("cls");  
    printf("\n\n\n\n\n\n\n\n\t*******************  您是否重新开始游戏 (Y/N) ?  *******************\n\n");  
    scanf("%s", buff);  
    ch = buff[0];  
    if (ch != 'n'&&ch != 'N') {  
        return false;  
    }  
    else {  
        printf("\n\n\n\n\t++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++\n");  
        printf("\t+++++++++++++++++++++++++   感谢您的使用   +++++++++++++++++++++++++\n", step);  
                printf("\t++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++\n\n");  
        system("pause");  
        exit(0);  
    }  
    return true;  
}  
void rank(score sco[],int n) {  
    int i, j;  
    sco[0] = sco[n];  
    for (i = 0; i < n; i++)  
        if (sco[n].steps2>sco[i].steps2) {  
            for (j = n; j > i; j--)  
                sco[j] = sco[j - 1];  
            sco[i] = sco[0];  
            break;  
        }  
    for (j = i - 1; j > 0; j--)  
        if (sco[i].steps2 == sco[j].steps2&&sco[i].steps < sco[j].steps)  
            sco[0] = sco[i], sco[i] = sco[j], sco[j] = sco[0], i = j;  
        else if (sco[i].steps2 == sco[j].steps2&&sco[i].steps == sco[j].steps)  
            if (sco[i].times < sco[j].times)  
                sco[0] = sco[i], sco[i] = sco[j], sco[j] = sco[0], i = j;  
}  
int check2(int *p, int n) {  
    int i, j, flag2 = 0;  
    for (i = 1; i < n*n - 1; i++)   
        for (j = 0; j < i; j++)   
            if (p[j] > p[i])  
                flag2++;  
    if (!flag2)  
        return 0;  
    else if (flag2 % 2 == 0)  
        return 2;  
    else  
        return 1;  
}  
bool check(int *p,int n) {  
    int i;  
    flag = true;  
    for (i = 0; i<n*n - 1; i++)  
        if (p[i] != i + 1)  
            flag = false;  
    if (flag) {  
        flag1 = false;  
        return false;  
    }  
    return true;  
}  
int operation(int *p,int n) {  
    scanf("%s", buff);  
    ch = buff[0];  
    if (ch >= 'a'&&ch <= 'z')  
        ch -= 32;  
    switch (ch) {  
    case 'A': if (y == n - 1) return 1;  
        p[x*n + y] = p[x*n + y + 1];  
        p[x*n + y + 1] = 0;  
        y++;  
        step++;  
        return 1;  
    case 'W': if (x == n - 1) return 1;  
        p[x*n + y] = p[(x + 1)*n + y];  
        p[(x + 1)*n + y] = 0;  
        x++;  
        step++;  
        return 1;  
    case 'D': if (y == 0) return 1;  
        p[x*n + y] = p[x*n + y - 1];  
        p[x*n + y - 1] = 0;  
        y--;  
        step++;  
        return 1;  
    case 'S': if (x == 0) return 1;  
        p[x*n + y] = p[(x - 1)*n + y];  
        p[(x - 1)*n + y] = 0;  
        x--;  
        step++;  
        return 1;  
    case 'R': return 2;  
    case 'M': return 3;  
    case 'Q': printf("\n\n\t********************* 您是否要离开游戏 (Y/N) ? *********************\n\n");  
        scanf("%s", buff);  
        ch = buff[0];  
        if (ch == 'y' || ch == 'Y')  
            return 4;  
        else  
            return 1;  
    default: return 1;  
    }  
    return 0;  
}  
void map(int *p, int n) {  
    int i, j;  
    system("cls");  
    printf("\n\n\n");  
    for (i = 0; i < n; i++)  
    {  
        printf("\t");  
        for (j = 0; j < n; j++)  
        {  
            if (p[n*i + j] != 0)  
                printf("%-4d", p[n*i + j]);  
            else  
                printf("    ");  
        }  
        printf("\n\n");  
    }  
    printf("\n\t按方向键移动卡片至无卡片的地方  W:上 S:下 A:左 D:右 M:返回菜单 R:换图 Q:退出\n\n");  
    finish = clock();  
    printf("\n\t\t\t\t步数: %d\t 使用时间: %.3f 分钟 \n\n", step, (double)(finish - start) / 40000);  
}  
void reset(int *p, int n) {  
    int i, j, flag2;  
    system("cls");  
    do {  
        for (i = 0; i < n*n - 1; i++) {  
            do {  
                flag2 = 1;  
                p[i] = rand() % (n*n - 1) + 1;  
                for (j = 0; j < i; j++)  
                    if (p[i] == p[j])  
                        flag2 = 0;  
            } while (!flag2);  
        }  
        flag2 = check2(p, n);  
        if (flag2 == 1) {  
            flag2 = p[n*n - 2];  
            p[n*n - 2] = p[n*n - 3];  
            p[n*n - 3] = flag2;  
        }  
    } while (!flag2);  
    p[n*n - 1] = 0;  
    for (i = 0; i<n; i++)  
        for (j = 0; j<n; j++)  
            if (p[i*n + j] == 0){  
                x = i;  
                y = j;  
            }  
}  
void help() {  
    int i = 0;  
    system("cls");  
    printf("\n\n\n\n\t--------------------------------+ 基本操作 +--------------------------------\n\n");  
    printf("\n\n\t按方向键移动卡片至无卡片的地方  W:上 S:下 A:左 D:右 M:返回菜单 R:换图 Q:退出\n\n");  
    printf("\n\n\t---------------------------+ 浅悠悠（王骏）制作 +---------------------------\n\n");  
    if (label == 0)  
        printf("\n\n\t--------------------------+ 暂时没有任何游戏记录 +--------------------------\n\n");  
    else  
        for (i = 1; i <= label; i++)  
            printf("\n\n\t  第%02d名：%-18s  步数：%-5d   阶数：%-5d   时间：%-6.3lf分钟\n\n",  
                i, sco[i].name, sco[i].steps, sco[i].steps2, sco[i].times);  
    printf("\n\n\t----------------------------+ 按任意键返回菜单 +----------------------------\n\n");  
    system("pause");  
}  
void game() {  
    int n, *p;  
    int mark;  
    do {  
        system("cls");  
        printf("\n\n\n\n\t------------------+ 请输入阶数（推荐3——20阶） +------------------\n\n");  
        scanf("%d", &n);  
        if (n > 1)  
            p = (int*)calloc(n*n, sizeof(int));  
        else  
            printf("\t********************** 您输入有误，请重新输入 **********************\n\n"), system("pause");  
    } while (n <= 1);  
next1:  
    step = 0;  
    start = clock();  
    reset(p, n);  
next2:  
    map(p, n);  
    if (check(p, n) == false) {  
        printf("\n\n\t=================+ 恭喜您完成游戏，请输入您的姓名 +=================\n\n");  
        scanf("%s", sco[++label].name);  
        sco[label].steps = step;  
        sco[label].steps2 = n;  
        sco[label].times = (double)(finish - start) / 40000;  
        rank(sco, label);  
        if (over() == false)  
            return;  
    }  
    mark = operation(p, n);  
    if (mark == 1)  
        goto next2;  
    else if (mark == 2)  
        goto next1;  
    else if (mark == 3)  
        return;  
    else if (mark == 4)  
        if (over() == false)  
            return;  
    free(p);  
}  
int main(){  
    srand((int)time(0));      
    do {  
        system("cls");  
        printf("\t-------------+ 欢迎来到浅悠悠数字拼图，请选择您的操作 +-------------\n\n");  
        printf("\t-----+  1.开始游戏  +-----+  2.帮助  +-----+  0(或其他).退出  +-----\n\n");  
        printf("\t++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++\n\n");  
        scanf("%s", buff);  
        ch = buff[0];  
        switch (ch){  
        case'1':  
            game(); break;  
        case'2':  
            help(); break;  
        case'0':  
            exit(0);  
        default:  
            exit(0);  
        }  
    } while (ch != '0');  
    return 0;  
}